We have 7 days in a week. And the first Day of the Date System is Sunday . And it should be. So, 01.01.0001, i.e., First Date of Christ was Sunday. We just number the days as follows. 0 = Sunday 1 = Monday 2 = Tuesday 3 = Wednessday 4 = Thursday 5 = Friday 6 = Saturday So, we can handle every day by the reminder of 7. Cause, u just see, after every 7 days the same day is repeated. Then, lets a rough Calculation. 01/01/0001 => Sunday = 0 Now, we just try to find out the day on 1st January on next year, i.e., 01/01/0002 0001 has 365 days. So, after 365 days which day will come? To find out the answer of this question we have to perform following calculation. 7 ) 365 ( 52 35 ----- 15 14 ---- 1 The reminder is 1, i.e.,Monday. But, using this method, it is very critical to find out the day of 1st January of 1988. So, we have an another idea. Find out how many Leap years are present before current year. Suppose it is L . So, L = y/4 If Current year is
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